(3x^4+2x^2-7)-(2x^4-x^3+4x^2)=

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Solution for (3x^4+2x^2-7)-(2x^4-x^3+4x^2)= equation:


Simplifying
(3x4 + 2x2 + -7) + -1(2x4 + -1x3 + 4x2) = 0

Reorder the terms:
(-7 + 2x2 + 3x4) + -1(2x4 + -1x3 + 4x2) = 0

Remove parenthesis around (-7 + 2x2 + 3x4)
-7 + 2x2 + 3x4 + -1(2x4 + -1x3 + 4x2) = 0

Reorder the terms:
-7 + 2x2 + 3x4 + -1(4x2 + -1x3 + 2x4) = 0
-7 + 2x2 + 3x4 + (4x2 * -1 + -1x3 * -1 + 2x4 * -1) = 0
-7 + 2x2 + 3x4 + (-4x2 + 1x3 + -2x4) = 0

Reorder the terms:
-7 + 2x2 + -4x2 + 1x3 + 3x4 + -2x4 = 0

Combine like terms: 2x2 + -4x2 = -2x2
-7 + -2x2 + 1x3 + 3x4 + -2x4 = 0

Combine like terms: 3x4 + -2x4 = 1x4
-7 + -2x2 + 1x3 + 1x4 = 0

Solving
-7 + -2x2 + 1x3 + 1x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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